How to solve...

Problem $2$

A parallel plate capacitor with plates of area $A,$ is operating with an electric field with magnitude $E$ and a total charge $Q.$ An electron $q$ departs from rest from the negatively charged plate and it moves freely until hitting the positively charged plate with a kinetic energy $K($see figure$).$

$A=121c{m}^2,E=2\mathrm{.}33*{10}^{-4}\frac{V}{m},K=6\mathrm{.}0*{10}^{-27}J,q=-1\mathrm{.}6*{10}^{-19}C,m_e=9\mathrm{.}1*{10}^{-31}k,$

$lo{n}_0=8\mathrm{.}85*{10}^{-12}\frac{C^2}{N{m}^2}$

Find the voltage $V$ between the parallel plates.

Find the speed of the electron when it reaches the positively charged plate.

What is the distance $d$ between the plates of the capacitor?

Find the capacitance $C$ of the capacitor.