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This Question : 3 pts 18 of 20 This Test : 100 pts possible 2 Question Help Determine the margin of error for a confidence interval to estimate the population proportion for the following confidence levels with a sample proportion equal to 0. 36 and n = 125 Click the icon to view a portion of the Cumulative Probabilities for the Standard Normal Distribution table . Cummulative probabilities to the left of z a . The margin of error for a confidence interval to estimate the population proportion for the 90 % confidence level is ( Round to three decimal places as needed . ) b . The margin of error for a confidence interval to estimate the population proportion for the 95% confidence level Cumulative Probabilities for the Standard format Distribution ( Round to three decimal places as needed . ) The margin of error for a confidence interval to estimate the population proportion for the 98 % confidence level is ( Round to three decimal places as needed . ) wes to the tipthe FIRST DIGIT OF Z SECOND DIGIT OF Z 5060 03040 05080 05120 05104 05140 45234 43270 05314 05354 15308 151 8 0578 6517 15653 65 46 1 5636 15075 9571 5053 9573 9583 9571 19719 5045 0545 16217 86255 01 293 90391 2054 ansel BOOZE CON 0920 90730 967 72 650 605 90570 10915 06950 0 0485 07014 0.7085 07123 07157 07100 07224 9 7257 6724) 0.7.359 07423 07454 07486 0.7517 07345 02042 03073 07304 07234 0230 03745 0783 98159 18180 08212 08258 98264 08390 08315 9 320 08365 08399 ON12 05138 05101 95185 08505 08521 08554 918517 03509 05021 0.4613 08685 8686 08708 08729 08749 98 6 5810 03530 CHRIS XENO USURY U.8WU 7 08425 08 4 USYOU USUYT 0 40 32 UHOH4 03060 941 0910 031 90192 09309 09272 09236 09251 0.5292 0.9305 0.931 9 9232 19245 09357 20406 09418 03420 09491 Enter your answer in each of the answer boxes 09452 19403 09154 09184 09405 90505 09515 09525 0.9535 0.9545 19554 0950 0957 3 9591 09590 0908 09616 Save for Late