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Given the function g(:c) = 6:123 27:1:2 72m, find the first derivative, g'(x). g'(w) = 18m254m72 0' Notice that g'(a:) = 0 when a: = 1, that is, g'( - 1) = 0- Now, we want to know whether there is a local minimum or local maximum at a: = 1, so we will use the second derivative value test. Find the second derivative, 9' '(m). 9' '(w) = Evaluate g"( 1). we: Based on the sign of this number, does this mean the graph of 9(3) is concave up_ or concave down at a: = 1? At :1: = 1 the graph Of g(:L') is Select an answer 0 . Based on the concavity of g(a:) at a: = 1, you can determine that at a: = 1 there is a local Select an answer 0 . Question Help: El Video