Question: I am struggling with these two problems the first one came out to .14874 which someone else on this site also got. However using the
I am struggling with these two problems the first one came out to .14874 which someone else on this site also got. However using the same formula for the second problem I am getting 3. something crazy. I was wondering am I forgetting a rule? is there something I am missing? is this the right formula and if so can you walk me thru it.
The proportion of brown M&M's in a milk chocolate packet is approximately 14% (Madison, 2013).Suppose a package of M&M's typically contains 52 M&M's.
Find the probability that
a.)Six M&M's are brown.
P(x=r)=nCr x PrQ^n-r
(X=6)=52C6 x.14^6 x 0.86^52-6
0.14874= 15%
b.)Twenty-five M&M's are brown. X=25 52C25 .14^25 0.86^52-25= 3.66166
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
