I have placed all the info here need help on these two problems please

Boiling Point Elevation/Freezing Point Depression T=mK where, for freezing point depression: T=T(puresolvent)T(solution) and for boiling point elevation: T=T(solution)T(puresolvent)m=(#molessolute/Kgsolvent)Kb=boilingpointelevationconstant.Kf=freezingpointdepressionconstant. Kb and Kf depend only on the SOLVENT. Below are some common values. Use these values for the calculations that follow. Use the References to access important values if needed for this question. The boiling point of benzene, C6H6, is 80.100C at 1 atmosphere. Kb (benzene) =2.53C/m In a laboratory experiment, students synthesized a new compound and found that when 12.55grams of the compound were dissolved in 216.7 grams of benzene, the solution began to boil at 80.479C. The compound was also found to be nonvolatile and a non-electrolyte. What is the molecular weight they determined for this compound? g/mol Use the References to access important values it needed for this question. The freezing point of ethanol, CH3CH2OH, is 117.300C at 1 atmosphere. Kf( ethanol) =1.99C/m In a laboratory experiment, students synthesized a new compound and found that when 12.58grams of the compound were dissolved in 251.2 grams of ethanol, the solution began to freeze at 117.844C. The compound was also found to be nonvolatile and a non-electrolyte. What is the molecular weight they determined for this compound? g/mol 9 more group attempts remaining