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Consider an object moving along a line with the following velocity and initial position. v(t)=18 2? on [0,4]; 5(0) = 4 Determine the position function for t2 0 using both the antiderivative method and the Fundamental Theorem of Calculus. Check for agreement between the two methods. To determine the position function for t 2 0 using the antiderivative method, rst determine how the velocity function and the position function are related. Choose the correct answer below. A. The position function is the absolute value of the antiderivative of the velocity function. B. The position function is the derivative of the velocity function. 3 C. The position function is the antiderivative of the velocity function. D. The velocity function is the antiderivative of the absolute value of the position function. Which equation below will correctly give the position function according to the Fundamental Theorem of Calculus? t t A. 5(0): s(t) + Iv(x)dx 6' B. s(t) = s(O) + Iv(x)dx 0 0 b b c. s(t) = 5(0) + Iv(t)dt D. s(t) = Iv(t)dt a 8 Determine the position function for t: 0 using both methods. Select the correct choice below and ll in the answer box(es) to complete your choice. A- The same function is obtained using each method. The position function is s(t)= O 3- Different functions are obtained using each method. The position function obtained using the antiderivative method is s(t) = and the position function obtained using the Fundamental Theorem of Calculus is s(t) = C 0 l5 Screen Shot 2021-09-04 at 8.52.04 PM livl a a l llVlt@.llLQ5arCh Find the position and velocity of an object moving along a straight line with the given acceleration, initial velocity, and initial position. a(t) = 44, v(0) = 50, and 3(0) = 30 v(t) = D