I need some help solving the Physics problem.

A basketball player jumps straight up for a ball. To do this, he lowers his body 0.330 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.840 m above the floor. (a) Calculate his velocity (in m/s) when he leaves the floor. (Enter a number.) m/s (b) Calculate his acceleration (in m/s ) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.330 m. (Enter a number.) m/s2 (c) Calculate the force (in N) he exerts on the floor to do this, given that his mass is 106 kg. (Enter a number.) N