I really need help coming up with a 10 sentence memo regarding my problem below! (attached photos)

Instructions:

Provide a memo (at least 10 good sentences) summarizing your PERT/CPM findings. Include an opinion, make at least two decisions, and explain your reasons why.

Question 1 --- (100 points) "Pen's R Us produces many types of ball point pens and to handle a high level of uncertainty they have a highly automated manufacturing facility. Bart Simpson is the Operations Manager and he has determined that each batch of pens will go through the same processes. The following information represents the 8 steps and the minutes required to manufacture each batch of ball point pens. Most Likely Activity A - Check Order B - Order Materials C - Turn on Machines D - Make the "Barrel" E - Make the "ink tube" F - Add Pen Tip G - Fill ink and Cap H - Package Pens IP None A B, C B A D EF Optimistic 1 4 2 1 2 1 1 3 6 4 2 3 2 2 3 Pessimistic 5 8 6 3 4 3 5 3 Bart has asked you to create a map of the project and to determine the critical path activities and the number of minutes it will take to complete the manufacturing for each batch. In addition, Bart wants you to determine the following four probabilities: the batch will take more than 12 minutes, the batch will take less than 15 minutes, the 80th percentile batch processing time, and the 35ih percentile batch processing time. If a "Rush Order" is placed, we need to reduce the time it takes to manufacture a batch by 10%. If each activity of the pen production process can be reduced by 1 minutes and the "crash cost per minute" for each production activity is $200.00, what crash strategy would you recommend? In addition, show "proof" that your selected crash strategy will work. Project Map, Completion Time, and Critical Path: Please provide evidence of your "hand-written solution. Project Map CTE 14.63/mits. CPE A-BE- ESTEEEF Hasel 9.00/10 SCH End Slette t- A 6.002.78 12.10.02.18 GLAP ES EF IF 24.3 ..09.01.29 He S7 B 2.01.18 0 2.50 9.59 S4=8 C 3.33 H. GO SL 367 ER 3.38 s.cdc. SUGA DE 30-8A 2. dec S4=1167 G. 1. N.ML USUF 167 29 2A-ELS Indie Ophinsic By Passic Hain 2.33 0.44 none A A 41 4 2 6 For coch activity, and the expected mean time Cue) = (0+*m*P) 16, and varionce or (0-12-/36 Activity Bebe Vortance A 5 B 0.44 4.00 B, C 2M 0.11 3.00 0.01 A 0.11 G D 0.44 H EF 3 13.00 10.00 2 41 2 3 E F s ) 2.10 2 2 3 meantime (M)= (ottmtp) 16 Activity A: (M)= (1+42+5/6 = 2.33 B:69=14+46+36 = 6,00 CEO = (2+4(47676 24.00 D:(= (14(2+3)6 =2.00 E: CA = (2+4(3+46 = 3.00 F:(= (1+4(21+ 316 -2.00 G: (4=(1+4(2)+516 =2.33 1:044= (314(2)+31/6=3.00 variance o2 = (p=0)-736 =(5-1)" /36 = 0.44 O = (8-42/36 = 0.44 o=66-2/36 -0.441 O = (3-1)/36 = 0.11 o = (4-21-/36 = 0.11 o =(3-1/7/36 = 0.11 o=(5-1136 = 0.44 Of=13-3-736=0.00 respective expected times and variances. The expected List all paths from start to end through and their Ume of each path is the sum of expected time of each activity poth is the sum of individua variance of each on that poth. Similarly, variance of each activity on that poth. Standard deviation is equal to square root of variance. Path Expected time A-B-D-G 12.67 A-B-E-H 14.33 110.67 144 1.33 0.560 Critical path is the longest path. Critical path is A-B-E-H Project completion is equal to expected time of criticalph Project completion time: 14.33 Variance std. den 1.20 1.44 1.00 (A-C-D-G A-E-H 1,20 0.75 Probability Analysis: Please provide evidence of your "hand-written solution. finbability Analysis: Foc minutes 2 volue = (12-14.394-2.33 PL2) = NORMSDTST (+2.33) - 0.0098 Probability that pencetul be completed within 2 minutes 0.0098 For 15 minutes, 2 valve (15-14 33/1 = 0.667 PA NORMSDIST (0.47)=0.775 Probability that project will be completed within 12 minutes 990,7415 percentile, z valoe: NORMSINV.CO.X) = 0.8416 Comdelion time: 14.3 +0.9414 (1)=15.17 80 percenkile batch procesing time. 16.17minutes for 35 percentile, zvoke NRMSINN (0,36) = -0.3853 Completion time = 14.33 -0.3953(1) = 15.95 35 percentile hotch processing time = 13.95 minutes For 8011 Crash Analysis: Please provide evidence of your "hand-written solution. Crash Analysis: on critical For 10% reduction, target project completion time 14.33 (1-10% = 12.9 minutes. Critical path is A-B-E the the next longest path is A-B-D-G, which is less than target completion time of 12.9 minutes. Therefore, crashin of any other path, than critical path is not required... any However, it is better to croch an activity path, if it is also on the second longest path. Actritis. A and B are activity B has a longest expected time. Usually, it is common on both paths. Of these two easier to crash an activity of longer duration, then shorter. Thereforces activity B should be crashed by 10% of 14.33, ic. 1.433 minutes. Total cost of crashing = 1.433 (200) = $287.67