I want the answer like second pic ( optimaly not initial ). No one answerd me yet

Solve the following transportation problem optimally 3 500 1 3 000 5 9 400 6 2 8 300 600 Example Problem D. Si D2 D u S 2 2000 1 2 Initial solution: Northwest corner D D, D S s, 1 2 2 2000 700 1300 S2 1 3 1 500 500 53 5 6 41200 700 500 d 700 2500 500 S2 1 3 1 500 S 5 6 4 1200 700 2500 500 d v Z= (700)(1)+(1300)(2)+(500)(3)+(700)(6)+(500)(4) Another initial solution: Minimum cost D. D D. S S 1 2 2 2000 700 1300 S2 1 3 1 500 500 S 5 6 4 1200 1200 d 700 2500 500 Another initial solution D. D2 D3 S u S1 1 2 2 2000 2000 S2 1 3 1 500 500 S 5 6 4 1200 700 500 d 700 2500 500 v Z= (2000)(2)+(500)(1)+(700)(5)+(500)(6) Z= (700)(1)+(1300)(2)+(500)(1)+(1200)(6) Compute u; and v: Start by selecting one u; or one v; and setting it equal to zero Hint: Select the one associated with the most basic variables u 2 S D. 1 700 1 S2 3 If we set V2 = 0, then For basic variable x12, Uz+V2-2=0 and hence u = 2 For basic variable X22, Uz+V2-3=0 and hence uz = 3 For basic variable X32, Uz+V2-6=0 and hence uz = 6 For basic variable X11, 4, +V7-1=0 and hence v2 = -1 For basic variable X33, Uz+V3-4=0 and hence vz = -2 D2 D. si 2 2 2000 1300 3 1 500 500 6 4 1200 700 500 2500 500 0 -2 S; 5 6 d 700 -1 D. u S 2 2000 S2 1 500 Compute u; and v/ for non-basic variables: For non-basic variable X13, U4+v3-2=2+(-2)-2=-2 For non-basic variable X21, U2+V7-1= 3+(-1)-1=1 For non-basic variable X23, uz+V2-1= 3+(-2)-1=0 For non-basic variable Xz, uz+v7-5= 6+(-1)-5=0 D D2 12 700 1300 1 2 3 500 5 6 700 700 2500 S 1200 4 500 500 d V X21 is entering Maximum increase in X21 = min(700, 500) Solve the following transportation problem optimally 3 500 1 3 000 5 9 400 6 2 8 300 600 Example Problem D. Si D2 D u S 2 2000 1 2 Initial solution: Northwest corner D D, D S s, 1 2 2 2000 700 1300 S2 1 3 1 500 500 53 5 6 41200 700 500 d 700 2500 500 S2 1 3 1 500 S 5 6 4 1200 700 2500 500 d v Z= (700)(1)+(1300)(2)+(500)(3)+(700)(6)+(500)(4) Another initial solution: Minimum cost D. D D. S S 1 2 2 2000 700 1300 S2 1 3 1 500 500 S 5 6 4 1200 1200 d 700 2500 500 Another initial solution D. D2 D3 S u S1 1 2 2 2000 2000 S2 1 3 1 500 500 S 5 6 4 1200 700 500 d 700 2500 500 v Z= (2000)(2)+(500)(1)+(700)(5)+(500)(6) Z= (700)(1)+(1300)(2)+(500)(1)+(1200)(6) Compute u; and v: Start by selecting one u; or one v; and setting it equal to zero Hint: Select the one associated with the most basic variables u 2 S D. 1 700 1 S2 3 If we set V2 = 0, then For basic variable x12, Uz+V2-2=0 and hence u = 2 For basic variable X22, Uz+V2-3=0 and hence uz = 3 For basic variable X32, Uz+V2-6=0 and hence uz = 6 For basic variable X11, 4, +V7-1=0 and hence v2 = -1 For basic variable X33, Uz+V3-4=0 and hence vz = -2 D2 D. si 2 2 2000 1300 3 1 500 500 6 4 1200 700 500 2500 500 0 -2 S; 5 6 d 700 -1 D. u S 2 2000 S2 1 500 Compute u; and v/ for non-basic variables: For non-basic variable X13, U4+v3-2=2+(-2)-2=-2 For non-basic variable X21, U2+V7-1= 3+(-1)-1=1 For non-basic variable X23, uz+V2-1= 3+(-2)-1=0 For non-basic variable Xz, uz+v7-5= 6+(-1)-5=0 D D2 12 700 1300 1 2 3 500 5 6 700 700 2500 S 1200 4 500 500 d V X21 is entering Maximum increase in X21 = min(700, 500)