I want the digital circuit design For this expression

$D_3=$ ground

$D_2\frac{?}{b}=ar(A)\frac{*}{b}ar(B)\frac{*}{b}ar(C)*D\frac{+}{b}ar(A)*B*C\frac{*}{b}ar(D)$

$D_1\frac{?}{b}=ar(A)\frac{*}{b}ar(B)\frac{*}{b}ar(C)\frac{*}{b}ar(D)\frac{+}{b}ar(A)\frac{*}{b}ar(D)*C*D$

$\frac{+}{b}ar(A)*B*C\frac{*}{b}ar(D)$

$D_0\frac{?}{b}=ar(A)\frac{*}{b}ar(B)\frac{*}{b}ar(C)\frac{*}{b}ar(D)\frac{+}{b}ar(A)\frac{*}{b}ar(B)*C*D\frac{+}{b}ar(A)*\frac{*}{b}ar(C)*D$