The primary winding of the transformer has a terminal voltage of Vsource=240 V. The turns ratio...

    

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The primary winding of the transformer has a terminal voltage of Vsource=240 V. The turns ratio of the transformer is 10:40 (a =0.25); note that Np 10 and Ns = 40. The impedances of this transformer referred to the primary side are, Req = 0.0492, Xeq = 0.12592, Rc = 8092, XM = 2592. If the primary current of the transformer is ip = 7.07 <-36.8° A, what is the secondary current of this transformer? Do not ignore the excitation branch of the transformer in your calculations. Use the equations aVs = Vp - Ip(0.04 -j0.125), IEX=aVs/Rc - aVs/jXm, and Is a = Ip - IEX [5 points) Calculate the load voltage assuming that the load is connected to the secondary winding and assuming that the primary current is ip =7.07<-36.8° A. [5 points) The primary winding of the transformer has a terminal voltage of Vsource=240 V. The turns ratio of the transformer is 10:40 (a =0.25); note that Np 10 and Ns = 40. The impedances of this transformer referred to the primary side are, Req = 0.0492, Xeq = 0.12592, Rc = 8092, XM = 2592. If the primary current of the transformer is ip = 7.07 <-36.8° A, what is the secondary current of this transformer? Do not ignore the excitation branch of the transformer in your calculations. Use the equations aVs = Vp - Ip(0.04 -j0.125), IEX=aVs/Rc - aVs/jXm, and Is a = Ip - IEX [5 points) Calculate the load voltage assuming that the load is connected to the secondary winding and assuming that the primary current is ip =7.07<-36.8° A. [5 points)