Identify the error or errors in this argument that supposedly shows that if AAx$[P(x)vvQ(x)]$ is true then

AAxP$(x)vvAAxQ(x)$ is true.

AAx$(P(x)vvQ(x)),$ Premise

$P(c)vvQ(c),$ Universal instantiation from $(1)$

$P(c),$ Simplification from $(2)$

AAxP$(x),$ Universal generalization from $(3)$

$Q(c),$ Simplification from $(2)$

AAxQ$(x),$ Universal generalization from $(5)$

AAx$(P(x)vvAAxQ(x))$ Conjunction from $(4)$ and $(6)$