If dy/dt=(y5) 2 , then y(t)=5 is an equilibrium solution. Suppose y(t) is a solution with initial-value
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Question:
If dy/dt=(y−5)2, then y(t)=5 is an equilibrium solution. Suppose y(t) is a solution with initial-value y(3)=7 . What we can conclude based off of the theory? (Please choose only one best answer/option)
(a) y(t)-> 5 as t-> infinity
(b) y(t)-> infinity as t-> infinity
(c) y(t)-> 5 as t increases
(d) y(t)-> infinity as t Increases
Related Book For
Essentials of Business Statistics
ISBN: 978-0078020537
5th edition
Authors: Bruce Bowerman, Richard Connell, Emily Murphree, Burdeane Or
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