In the benzene adsorber of Example 9.6, the flow rate is increased to (0.25 mathrm{~m}^{3} / mathrm{s}).

Question:

In the benzene adsorber of Example 9.6, the flow rate is increased to \(0.25 \mathrm{~m}^{3} / \mathrm{s}\). Calculate the breakthrough time and the fraction of the bed adsorption capacity that has been used at breakthrough. At the increased flow rate, the new value of \(K_{c} a=10.5 \mathrm{~s}^{-1}\).

Data From Example 9.6:-

Air at 294 K and 1 atm enters a fixed-bed adsorber at a flow rate of 0.146 m3/s with a benzene vapor concentration of 29 g/m3. The cylindrical adsorber is 0.61 m inside diameter and is packed to a height of 1.83 m with 331 kg of silica gel particles having an effective diameter of 2.6 mm and an external porosity of 50%. The adsorption isotherm for benzene has been determined experimentally and found to be linear over the concentration range of interest, given by q = κc, where q is in kg benzene/ kg gel, c is in kg benzene/m3 of gas, and κ = 4.127 m3 of gas/kg of gel. It has been estimated that the overall volumetric mass-transfer coefficient for the conditions prevailing in the bed is Kca = 8.79 s–1. Assuming isothermal and isobaric operation, calculate

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