Question: If given an equation for a plane, 5 (x-1) + 2 (y + 7)-3(z-5) = 0, how can I find two points on the

If given an equation for a plane, 5 (x-1) + 2 (y

If given an equation for a plane, 5 (x-1) + 2 (y + 7)-3(z-5) = 0, how can I find two points on the plane? I know of (1, -7, 5) but how do I find another point?

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