Question: If we apply Rolle's Theorem to the function f(:r;) = 2:32 83: 2 on the interval [0, 4], how many values of c exist such

 If we apply Rolle's Theorem to the function f(:r;) = 2:32

83: 2 on the interval [0, 4], how many values of c

If we apply Rolle's Theorem to the function f(:r;) = 2:32 83: 2 on the interval [0, 4], how many values of c exist such that f '(c) = 0? What is the value of c? If we try to apply Rolle's Thorem to the function f(:c) = 2:232 8a: 2 on the interval [ 3, 11], which of the following conditions is not met? f0!) 79 fa?) differentiability on [ 3, 11] continuty on [ 3, 11]

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