Question: I'm having trouble with the following mySQL problem and code. I've included table structure also, if that helps. 6. Write a SELECT statement that returns
I'm having trouble with the following mySQL problem and code. I've included table structure also, if that helps.
6. Write a SELECT statement that returns one row for each customer that has orders with these
columns:
The email_address from the Customers table
A count of the number of orders
The total amount for each order (Hint: First, subtract the discount amount from
the price. Then, multiply by the quantity.)
Return only those rows where the customer has more than 1 order.
Sort the result set in descending sequence by the sum of the line item amounts.
SELECT email_address, COUNT(o.order_id) as number_of_orders, sum((item_price-discount_amount)*quantity) As Total
FROM Customers c JOIN Orders o
ON c.customer_id = o.customer_id
JOIN (
SELECT order_id,
CASE WHEN item_priceFROM order_items ) oi on oi.order_id =o.order_idGROUP BY email_addressHAVING COUNT (o.order_id) > 1ORDER BY number_of_orders DESC;customers v Columns customer id email address password first name ast name shipping address id billing address id v P Indexes PRIMARY email address Foreign Keys Triggers
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