I'm solving a certain problem, but I can't seem to get the correct answer to this problem, so I was hoping you could correct me in my solution. For the problem, we are given the following data: In the image, the arm immobilization with a sling is visible, the upper arm is fixed, and from point B to the left, movement is allowed upwards and downwards. We have the mass of the plaster, which is 0.7 kg, and a tension at an angle of 65 degrees with respect to the horizontal. The forearm has a weight of 20 N, and the center of mass is at point C, right in the middle of point A and point B. The distance from point A to point B is 40 cm.

Body diagram hos X A C F . W 20 cm EFy = Toin D - forearm weight + Cast weight EFX = Toos (65 ) - R = 0 = TsIn (65. ) - 20N - 0. 7 kg ( 9.8 m / 53) = 0 Toos ( 6 5 . ) = R = Tsin ( 650 ) - 20 N- 6. 86N R = 29. 64 N 26.86 N T = SIn (65. ) - 29. 64 N R x 12. 53 sling tension = 29. 64 N Reaction * 12.53/T 65