Question: I'm stuck on f, the function is defined at the top. Any help would be appreciated. Thank you! The problems on this page continue to

I'm stuck on f, the function is defined at the top. Any help would be appreciated. Thank you!

The problems on this page continue to refer to f (x) = x3 + 2x2 - 4x + 1. f'( X ) = 3 *2+4x - 4 d) Without graphing, find the intervals of concavity of f. (-10, -2/3) -2/3 (-2/3, 00) f " ( x ) = 6 x + 4 t. V 0 = 6*+ 4 F " (x ) + +4 - 4 = 6x Down Up X = - 4. =-2 concare down: (-0, 3) Concave up: ( - 38, 00 ) e) Without graphing, find the inflection point(s) of f. f ( - 3 ) = (3 )+ 2(- 3) - 4(-3 ) +1 27 +3 + 8 + 1 - 8+ (8 .3) +(8.9) +27 - - 8+24+72+27 1 27 27 27 inflection points = (s, t f) Without graphing, make a list of at least two intervals where the Extreme Value Theorem holds
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