import math

def axial$\_$stretch$($d$,$ l$,$ F$)$:

# Cross$-$sectional area calculation

A $=$ math.pi $*($d $/1000)**2/4$ # Convert diameter from mm to m

# Elastic modulus for steel

E $=200$e$9$ # Pa

# Computing the stretch

delta $=($F $*$ l$)/($A $*$ E$)$

return delta

# Taking input values

d $=$ float$($input$())$

l $=$ float$($input$())$

F $=$ float$($input$())$

# Calculating the axial stretch

stretch $=$ axial$\_$stretch$($d$,$ l$,$ F$)$

# Printing the result

print$($f$"$The rod will stretch $\{$stretch:$\mathrm{.}3$f$\}$ mm$.")$