Question: In a queueing system, customers arrive once every 4 seconds (standard deviation - 4) and services take 3 seconds (standard deviation = 5:1), (Do not

In a queueing system, customers arrive once every 4 seconds (standard deviation - 4) and services take 3 seconds (standard deviation = 5:1), (Do not round intermediate calculations. Round your answer to three decimal places.) What is the average time a customer will spend in the system (in seconds)? seconds

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