In a town, 45% of all households have a pet, 35% have children, and 40% of all households with children have a pet. Using these definitions:

P = event household has a pet

C = event household has children

a. Complete the following contingency table

b. From part (a) or otherwise, answer the following:

i. What is the probability that a randomly selected household has neither pets nor children?

ii. What proportion of households with children do not have a pet? iii. Find and interpret P(C | P).