In an injection moulding process, at 170C, polyethylene behaves as a power law fluid with the...
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In an injection moulding process, at 170°C, polyethylene behaves as a power law fluid with the shear stress (Pa) and shear strain rate (s¹) related by the following equation: T = 500 (y)-0.5 The flow of a power law fluid through a tube is given by: 2= [ (dP/dx) A flow rate of 5.9 m³/s is required down a tube of length 10 cm, along which the pressure drop is limited to 0.8 MPa. Calculate the minimum diameter needed for the tube. T (1/n)+3 In an injection moulding process, at 170°C, polyethylene behaves as a power law fluid with the shear stress (Pa) and shear strain rate (s¹) related by the following equation: T = 500 (y)-0.5 The flow of a power law fluid through a tube is given by: 2= [ (dP/dx) A flow rate of 5.9 m³/s is required down a tube of length 10 cm, along which the pressure drop is limited to 0.8 MPa. Calculate the minimum diameter needed for the tube. T (1/n)+3 In an injection moulding process, at 170°C, polyethylene behaves as a power law fluid with the shear stress (Pa) and shear strain rate (s¹) related by the following equation: T = 500 (y)-0.5 The flow of a power law fluid through a tube is given by: 2= [ (dP/dx) A flow rate of 5.9 m³/s is required down a tube of length 10 cm, along which the pressure drop is limited to 0.8 MPa. Calculate the minimum diameter needed for the tube. T (1/n)+3 In an injection moulding process, at 170°C, polyethylene behaves as a power law fluid with the shear stress (Pa) and shear strain rate (s¹) related by the following equation: T = 500 (y)-0.5 The flow of a power law fluid through a tube is given by: 2= [ (dP/dx) A flow rate of 5.9 m³/s is required down a tube of length 10 cm, along which the pressure drop is limited to 0.8 MPa. Calculate the minimum diameter needed for the tube. T (1/n)+3
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Related Book For
Numerical Methods For Engineers
ISBN: 9780071244299
5th Edition
Authors: Steven C. Chapra, Raymond P. Canale
Posted Date:
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