Question: (IN C++) Prompt the user to enter an integer n. If n is odd, then compute the following jump-factorial: 1-3+5-7++ (-1)n/2 *n; if n is

(IN C++) Prompt the user to enter an integer n. If n is odd, then compute the following jump-factorial: 1-3+5-7++ (-1)n/2 *n; if n is even, compute the following jump-factorial: 2*4*6**n; if n is negative or zero, the result is 0. Finally, output the result

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