Question: In co - current configuration ( Figure - 1 ) , a hydrocarbon liquid flowing through a r = 1 c m ( internal )

In co-current configuration (Figure-1), a hydrocarbon liquid flowing through a r=1cm(internal) radius heat exchanger tube with length 1m. The liquid enters at a temperature of =0 and is cooled by a boiling liquid on the outside of the tube, the latter liquid's boiling point is Tc=373K. We can model the hydrocarbon liquid temperature as a function of the tube coordinate z with the single differential equation:
mhCphdThdz=2rh(Tc-Th)
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where the heat transfer coefficient is given as h=550Wm2(K),Cph=2100JkgK, and the mass flow rate of the hydrocarbon stream is mh=0.5kgs.
Compute the hydrocarbon stream outlet temperature )=(1 and Tb vs Z
Figure I Heat exchanger co-current configuration
 In co-current configuration (Figure-1), a hydrocarbon liquid flowing through a r=1cm(internal)

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