Question: Let a (m). (a) Show that if 6 = 1, then b e (m). (b) If 6 = 1 and b1 = 1, show

Let a (m). (a) Show that if 6 = 1, then b 


Let a (m). (a) Show that if 6 = 1, then b e (m). (b) If 6 = 1 and b1 = 1, show that 6 = b1. (Hence for every E P(m) there exists an unique be (m) such that b = 1.)

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