In exercising, a weight lifter loses $0\mathrm{.}138$ kg water through evaporation, the heat required to evaporate the water coming from the weight lifter's body. The work done in lifting weights is $1\mathrm{.}98$ x $10^5$ J$.($a$)$ Assuming that the latent heat of vaporization of perspiration is $2\mathrm{.}42$ x $10^6$ J$/$kg$,$ find the change in the internal energy of the weight lifter. $($b$)$ Determine the minimum number of nutritional Calories of food that must be consumed to replace the loss of internal energy. $(1$ nutritional Calorie $=4186$ J$).$