Question: In order to crash the project given below by. 4 days, what will be the minimum cost of crashing? IMMEDIATE PREDECESSOR(S) NORMAL CRASH TIME NORMAL

In order to crash the project given below by. 4

In order to crash the project given below by. 4

In order to crash the project given below by. 4 days, what will be the minimum cost of crashing? IMMEDIATE PREDECESSOR(S) NORMAL CRASH TIME NORMAL TIME (DAYS) (DAYS) COST (5) 9 7 200 7 6 800 5 4 6 4 1100 9 6 1200 ACTIVITY . B C D E LO CRASH COST [+] 300 875 675 1300 1875 600 , The minimum cost of crashing is t (enter your response as a WHOLE NUMBER). Formulae: ES = Max{EF of all immediate predecessors) EF = ES + Activity time LF = Min{LS of all immediate following activities} LS = LF - Activity time Slack Time = LS-ES = LF - EF Crash cost - Normal cost Crash cost per day Normal time Crash time

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