Question: in python, A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To

in python,

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:

1) The year must be divisible by 4

2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400

Some example leap years are 1600, 1712, and 2016.

Write program that takes in a year and determines whether that year is a leap year.

Ex: If the input is:

1712 

the output is:

1712 is a leap year. 

Ex: If the input is:

1913 

the output is:

1913 is not a leap year. 

Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.

def is_leap_year(user_year)

Note: This is a lab from a previous chapter that now requires the use of a function

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