Question: In python code please! Write a Python program that finds the smallest multiple of 127 that is greater than n where n in a given
Write a Python program that finds the smallest multiple of 127 that is greater than n where n in a given positive number. Print out that multiple and test your code for at least 3 values of n. The definition statement of your program should be def multy(n) Your output statement should be of the form: The smallest multiple of 127 that is greater than bbb is SSSS. where bbb is the value n and SSSS is the multiple. The ancient Greeks knew that the iteration x_n + 1 = 1/2 (x_n + 2/x_n) would converge to squareroot2 if x_0 = 1. Write a Python program that takes a starting value as input and determines if the sequence converges or not. The sequence converges if |x_n + 1 - x_n| lessthanorequalto 10^-7. If it doesn't converge in 100 iterations, then we'll say the sequence doesn't converge. The definition statement of your program should be def squareroot2(x0) Your output .statement should be of the form: The sequence starting at X0X0X0 converges to XXXX in NNNN iterations. or The sequence starting at X0X0X0 doesn't converge. where X0X0X0 is the initial value x_0. XXXX is the value the sequence converges to and NNNN is the number of iterations it takes to converge
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