In the cell below is an example of a "nested loop." Beginning with your$\_$code from Question $5($and using the nested loop example below as a reference$),$ write a loop inside your loop from Question $5$ that calculates $(x+y{)}^2$ for every value of $y($i$.$e$.$ your Inner toop should be over the list of $y-$values$)$ and appends it to a new list $x{y}_{?}$squared. In your outer loop, print out that list.

If you've done this correctly, then the first list you get should look like the following:

$144,105\mathrm{.}0625,90\mathrm{.}25,81,72\mathrm{.}25,81,90\mathrm{.}25,105\mathrm{.}0625,144$

which is $(2+10{)}^{{?}^{{?}^{?}}}2,(2+8\mathrm{.}25{)}^{{?}^{{?}^{?}}}2,(2+7\mathrm{.}5{)}^{{?}^{{?}^{?}}}2,(2+7{)}^{{?}^{{?}^{?}}}2,(2+6\mathrm{.}5{)}^{{?}^{{?}^{?}}}2,(2+7{)}^{{?}^{{?}^{?}}}2,(2+7\mathrm{.}5{)}^{{?}^{{?}^{?}}}2,(2+8\mathrm{.}25{)}^{{?}^{{?}^{?}}}2,(2+10{)}^{{?}^{{?}^{?}}}2.$

The next list should be the result of $(4+10{)}^{{?}^{{?}^{?}}}2,(4+8\mathrm{.}25{)}^{{?}^{{?}^{?}}}2,(4+7\mathrm{.}5{)}^{{?}^{{?}^{?}}}2,(4+7{)}^{{?}^{{?}^{?}}}2,(4+6\mathrm{.}5{)}^{{?}^{{?}^{?}}}2,(4+7{)}^{{?}^{{?}^{?}}}2,(4+7\mathrm{.}5{)}^{{?}^{{?}^{?}}}2,(4+8\mathrm{.}25{)}^{{?}^{{?}^{?}}}2,(4+10{)}^{{?}^{{?}^{?}}}2$ because you should move on to the next value in the $x$ list. This will look like:

$196,150\mathrm{.}0625,132\mathrm{.}25,121,110\mathrm{.}25,121,132\mathrm{.}25,150\mathrm{.}0625,196$

Yes, this might seem a bit complicated $--$ that's totally expected. After all, you're still learning to write code! If you find yourself spending too much time to figure this out, make use of Teams or try to drop by office hours or help room hours. Making sure that 'you spend time on your own trying to work through pre$-$class activities like this one are important for making your time in class as productive as possible.