In the Midpoint Rule for triple integrals we use a triple Riemann sum to approximate a triple integral over a box $B,$ where $f(x,y,z)$ is evaluated at the center $)$ of the box $B_{\text{i}\text{j}\text{k}}.$ Use the Midpoint Rule to estimate the value of the integral. Divide $B$ into eight sub$-$boxes of equal size. $($Round your answer to two decimal places.$)$

${}_{B}6\sqrt[\phantom{2}]{x^2+y^2+z^2}dV,$ where $B=\{(x,y,z)|0x4,0y4,0z4\}$