Question: In this problem we consider an equation in differential form M dx + N dy = 0. The equation (4xy e - 4e sin(a) +

In this problem we consider an equation in differential form M dx + N dy = 0. The equation (4xy e - 4e sin(a) + 4ey) da + (4x ye * + 4ey)dy = 0 in differential form M da + N dy = 0 is not exact. Indeed, we have My - N . = For this exercise we can find an integrating factor which is a function of x alone since My - N x N can be considered as a function of x alone. Namely we have M(a) = Multiplying the original equation by the integrating factor we obtain a new equation M dx + N dy = 0 where M = N = Which is exact since My = N. = are equal. This problem is exact. Therefore an implicit general solution can be written in the form F(x, y) = C where F(x, y) =
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