In this task you can turn pages in a book either from the front or the back of the book. You always turn the page one at a time. If the book is n pages long and you want to turn to page p, what is the minimum number of pages to turn. Given n and p find and print the minimum number of pages that must be turned in order to arrive at page p.

Below is the correct code.

I dont understand why we have st=p//2 and en=n//2 and then why do we have return [st,en-st]? and what does it do?

def pageCount (n,p): st=p //2# spread from start en=n//2 \# spread from end return min ([ st, en-st ])