It means, if we double the length of the wire, its resistance will also be doubled,...

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It means, if we double the length of the wire, its resistance will also be doubled, and if its length is halved, its resistance would become one-half. Relation of resistance with area: The resistance R of a wire is inversely proportional to the area of cross-section A of the wire as: It means that a thick wire would have smaller resistance than a thin wire. After combining the equations (1) and (2) we get; 2m 5m 10m Q- A conductor has a resistance of 100, a length of 1 m, an area of 1 m, at 25 C. 0.1m Finf the magnitude of the resistance for the following cases at which one or more factors change: (Show your work) Length(1) 0.5m 12m 100m Area(A) 3m 0.5m RaL .....(1) 0.25 m 2m 2.5m R a 1/A 1.5m 0.01m (2) R & L/A R=PL/A...(3) Temperature(T) 25 C 75 C 25 C 100 C 150 C 5 C 1 C Resistance(R) It means, if we double the length of the wire, its resistance will also be doubled, and if its length is halved, its resistance would become one-half. Relation of resistance with area: The resistance R of a wire is inversely proportional to the area of cross-section A of the wire as: It means that a thick wire would have smaller resistance than a thin wire. After combining the equations (1) and (2) we get; 2m 5m 10m Q- A conductor has a resistance of 100, a length of 1 m, an area of 1 m, at 25 C. 0.1m Finf the magnitude of the resistance for the following cases at which one or more factors change: (Show your work) Length(1) 0.5m 12m 100m Area(A) 3m 0.5m RaL .....(1) 0.25 m 2m 2.5m R a 1/A 1.5m 0.01m (2) R & L/A R=PL/A...(3) Temperature(T) 25 C 75 C 25 C 100 C 150 C 5 C 1 C Resistance(R)

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The question youve presented involves calculating the resistance R of a conductor given different lengths l crosssectional areas A and temperatures T ... View the full answer