J$.$ Snyder and B$.$ Subramaniam, Chem. Eng. Sci., $49,5585(1994)].$ Ethylbenzene is fed at a rate of $0\mathrm{.}00344$ kmol$/$s to a $10\mathrm{.}0-$m$\text{'}$ PFR $($PBR$),$ along with inert steam did total pressure or $2\mathrm{.}4$ atm. Ihe steam$/$ethylbenzene molar ratio is initially, i$.$e$..$ parts $($a$)$ to $($c$),14\mathrm{.}5$:$1$ but can be varied. Given the following data, find the exiting molar flow rates of styrene, ben$-$ Zene. neoluene alone with Sst$/$br for the following inlet temperatures when the reactor is operated adiabatically: Hall of Fame $($a$)$ In $=800$ K $$D$1$o $=930$K $($c$)$ To $=1100$ K Find the ideal inlet temperature for the production of styrene for a steam$/$ethylbenzene ratio of $58$:$1.$ Hint: Plot the molar flow rate of styrene versus To$.$ Explain why your curve looks the way i does $($e$)$ Find the ideal steam$/$ethylbenzene ratio for the production of styrene at $900$ K$.$ Hint: See part $($d$).$ It is proposed to add a countercurrent heat exchanger with Ua $=100$ kJ$/$m$/$min$/$K$,$ where T$,$ is virtually constant at $1000$ K$.$ For an entering stream to ethylbenzene ratio of $20,$ what would you suggest as an entering temperature? Plot the molar flow rates and Ds$/$Br What do you believe to be the major points of this problem? $($h$)$ Ask another question or suggest another calculation that can be made for this problem. Additional information Methane $68$J$/$mol$-$K Ethylene $90$J$/$mol$-$K Benzenel $201$ J$/$mol$-$K Toluene $249$ J$/$mol $-$ K p $=2137$ kg$/$m of pellet $=0\mathrm{.}4$ AHRIEB $=118,000$ kJ$/$kmol ethylbenzene AFREE $=105,200$ kJ$/$kmol ethylbenzene Heat capacities Styrene $273$ J$/$mol$-$K Ethylbenzene $299$ J$/$mol$-$K Hydrogen $30$ J$/$mol$-$K Steam $40$ J$/$mol$-$K b$=-17\mathrm{.}34$b$2=1\mathrm{.}30210$K bs $--2\mathrm{.}314$X $10-10$ K$-3$ bs $=1\mathrm{.}302$ X $10-6$ K$-2$ b$6=-4\mathrm{.}931\backslash$times $10-*$ K$-1$ The kinetic rate laws for the formation of styrene $($St$),$ benzene $($B$),$ and toluene $($T$),$ respectively, are $($kmol$/$m$-$s$)1-$ P$(1-6)6$Xp $132392-25,00($PEN$)($kmol$/$m$\text{'}-$