Lab 17 Hypothesis Tests II Score: 0/91 0/7 answered Progress saved Done VO CO . . . . Question 7 0/13 pts 95 2 3 0 Details The Pew Internet and American Life Project surveyed 306 adults in 2019, asking them about their texting habits. Among men, the mean number of text messages sent per day was 46.5, and among women it was 51.9. Assume that 105 men and 201 women were sampled, and that the standard deviations were 21.5 for men and 22.1 for women. Can you conclude that the mean number of text messages differs between men and women? Use the a = 0.02 level. a. State the null and alternative hypotheses. Ho : ? Y 2 7 Select an answer H1 : ? Y ? Y Select an answer b. Find the critical value and sketch the rejection region. Sketch of Rejection Region: -3 -2 -1 0 2 w - Q O -3 -2 0 2 Q O -2 -1 0 2 QLab 17 Hypothesis Tests II Score: 0/91 0/7 answered Progress saved Done VOCO . . . . Question 5 0/13 pts 95 3 0 Details Medical researchers performed a comparison of two drugs, clopidogrel and ticagrelor, which are designed to reduce the risk of heart attack or stroke in coronary patients. A total of 5212 patients were given clopidogrel, and 6295 were given ticagrelor. Of the clopidogrel patients, 552 suffered a heart attack or stroke within one year, and, of the ticagrelor patients, 589 suffered a heart attack or stroke. Can you conclude that the proportion of patients suffering a heart attack or stroke is less for ticagrelor? Use the o = 0.07 level. a. State the null and alternative hypotheses. Ho: ? ? Select an answer H 1 : ? v ? Y Select an answer b. Find the critical value and sketch the rejection region. Sketch of Rejection Region: -3 -2 -1 0 1 2 3 Q -3 -2 -1 0 1 2 Q -3 -2 0 2 w Q OCritical value(s): D (Ifthere are two critical values, list both values separated by a comma) c. Find the test statistic. l: d. Find the p-value. C] e. Decide: Ho f. Conclusion: At a: = 0.07 significance level, there enough evidence to conclude that the proportion of patients suffering a heart attack or stroke is less for ticagrelor. Critical value(S): (If there are two critical values, list both values separated by a comma) c. Find the test statistic. d. Find the p-value. e. Decide: Select an answer V Ho f. Conclusion: At a = 0.01 significance level, there Select an answer v | enough evidence to conclude that the mean credit score is more than 720.Lab 17 Hypothesis Tests II Score: 0/91 0/7 answered Progress saved Done . Question 6 0/13 pts 95 3 0 Details Credit scores are used by banks and other lenders to determine whether someone is a good credit risk. Scores range from 300 to 850, with a score of 720 or more indicating that a person is a good credit risk. An economist finds that a simple random sample of 169 people had a mean credit score of 735 with a standard deviation of 80. Can the economist conclude that the mean credit score is more than 720? Use the o = 0.01 level. a. State the null and alternative hypotheses. Ho: ? Y ? Y ? Y H1 : ? Y b. Find the critical value and sketch the rejection region. Sketch of Rejection Region: -3 -2 -1 0 2 w - Q -3 -2 -1 0 2 w - Q w - Q OCritical value(s): (If there are two critical values, list both values separated by a comma) c. Find the test statistic. d. Find the p-value. e. Decide: Select an answer Ho f. Conclusion: At a = 0.02 significance level, there Select an answer enough evidence to conclude that the mean number of text messages differs between men and women