All members of the truss shown below have a cross-sectional area of 2 in2 and elastic...

 

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All members of the truss shown below have a cross-sectional area of 2 in2 and elastic modulus of 29,000 ksi. 2 k L 4 k (4) 10' (1) 10' (3) (2) Consider the loading at node 4. (a) By hand, use the Direct Stiffness Method to obtain the free DOFs. (b) Using Matlab® (or equivalent), use the Direct Stiffness Method to obtain the free DOFs. (c) Using Matlab® (or equivalent), plot the deflected shape superimposed on the undeflected shape of the structure. All members of the truss shown below have a cross-sectional area of 2 in2 and elastic modulus of 29,000 ksi. 2 k L 4 k (4) 10' (1) 10' (3) (2) Consider the loading at node 4. (a) By hand, use the Direct Stiffness Method to obtain the free DOFs. (b) Using Matlab® (or equivalent), use the Direct Stiffness Method to obtain the free DOFs. (c) Using Matlab® (or equivalent), plot the deflected shape superimposed on the undeflected shape of the structure. All members of the truss shown below have a cross-sectional area of 2 in2 and elastic modulus of 29,000 ksi. 2 k L 4 k (4) 10' (1) 10' (3) (2) Consider the loading at node 4. (a) By hand, use the Direct Stiffness Method to obtain the free DOFs. (b) Using Matlab® (or equivalent), use the Direct Stiffness Method to obtain the free DOFs. (c) Using Matlab® (or equivalent), plot the deflected shape superimposed on the undeflected shape of the structure.

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a By hand Using the direct stiffness method here are the steps to obtain the free DOFs at node 4 ... View the full answer