Question: Let /(2) = 1 I - 5 and 9(I) = 2z + 10. Then (f o g) (5) = (fog)(z) = Let /(z) = 52

 Let /(2) = 1 I - 5 and 9(I) = 2z

Let /(2) = 1 I - 5 and 9(I) = 2z + 10. Then (f o g) (5) = (fog)(z) = Let /(z) = 52 - 5 and g(z) = 17 - 32 + 4. Then (fog) (1) = (go f)(I) = Let f (z) =- 1 and 9(z) = " + 5 . I Then (f o g)(z) = (go f)(=) = Use the table below to find: (f . g)(13) = (9. f)(-8) = (fo f)( - 6) = (909)(12) = X -8 -7 -6 5 10 11 12 13 f(z) 12 13 -6 -7 8 11 5 10 9(1) 11 10 -7 12 6 8 5 13 Function Composition Using Graphs Use the graphs for f() and g() to evaluate the expressions below. Write your answer as an integer or a reduced fraction. 2 3 4 56 1-2 flo( - 3)) =] 9(f( - 4)) = Given that f (z) = 23 + 9r and g(z) = z + 7, calculate (a) fog(z)= (b) go f(z)= (of of(=)= (d) go g(z)= Let f(z) = 3z + 3 and g(z) = 427 + 5z. After simplifying (fog)(z) = Given that f(x) = 4x - 4 and g(I) = 2 - x2, calculate (a) f(g(0))= (b) g(f(0))= 1 Let f(z) = -2 7 and g(z) = = + 2. Then (f o g)(1) = (go f)(z) = Let f(z) = - 1 I - 3 and g(x) = 21 + 10. Then (f o g) (3) = (fog)(z) = Let f(z) = 2z - 2 and g(z) = ' - 71 + 3. Then (fog) (3) = (9 . f)(z) =

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