Question: Let f(x) = 12x + 11 - 3e^x. Then the equation of the tangent line to the graph of f(x) at the point (0,8) is

Let f(x) = 12x + 11 - 3e^x. Then the equation

of the tangent line to the graph of f(x) at the point

Let f(x) = 12x + 11 - 3e^x. Then the equation of the tangent line to the graph of f(x) at the point (0,8) is given by y = mx + b form=b =

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