Let f(x) = x2 - V6x. In order for the Intermediate Value Theorem to apply we must first check that f is Select an answer | on the interval [0,6]. You should verify this and be able to explain why it is the case. We check the value of f at the left endpoint of the interval [0,6]: -1 2 3 4 5 6 7 f( ) = And we check the value of f at the right endpoint of the interval [0,6]: -2 -1 2 3 4 5 6 7 The Intermediate Value Theorem guarantees a solution to f(@) = 21 in the interval (0,6) because f ( )S S f ( ) 210 -1 1 2 3 4 5 6 7The graph below is the function f(:13) 10-9-8-7-6-5-4-3-2-1 12345673911! Determine the following values. Enter "DNE" if a value does not exist, enter "00" (lower case "0") if the limit approaches positive infinity, or "oo" if the limit approaches negative innity. at) has an infinity discontinuity at'f ' at) hasjump discontinuity at l ' at) has a removable discontinuity at l