Let's imagine a block on a sheet of ice, with negligible friction. The block has a...

 

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Let's imagine a block on a sheet of ice, with negligible friction. The block has a mass of 5.00 kg. The block is currently moving to the right at 4.00 m/s. Let's say a rope is attached to this block, and it pulls horizontally on the block, also to the right, with a force of 13.0 N. With this force applied, the block moves a distance of 3.00 m to the right. How fast is the block moving at the end of this distance? There is a lot of information in this problem, but let's think for a moment how to approach it. We can use the work-kinetic energy theorem. That is, if we can find an initial kinetic energy, and find the work, we can then solve for the final kinetic energy. Knowing the final kinetic energy, we can find the final speed. Let's first find the initial kinetic energy. What is the kinetic energy (in 3) of the block when it is moving at 4.00 m/s? Next, let's calculate the work (in 3) done on the block by the rope. Let's imagine a block on a sheet of ice, with negligible friction. The block has a mass of 5.00 kg. The block is currently moving to the right at 4.00 m/s. Let's say a rope is attached to this block, and it pulls horizontally on the block, also to the right, with a force of 13.0 N. With this force applied, the block moves a distance of 3.00 m to the right. How fast is the block moving at the end of this distance? There is a lot of information in this problem, but let's think for a moment how to approach it. We can use the work-kinetic energy theorem. That is, if we can find an initial kinetic energy, and find the work, we can then solve for the final kinetic energy. Knowing the final kinetic energy, we can find the final speed. Let's first find the initial kinetic energy. What is the kinetic energy (in 3) of the block when it is moving at 4.00 m/s? Next, let's calculate the work (in 3) done on the block by the rope.

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First lets calculate the initial kinetic energy of the block when it is moving at 400 ms Given Mass ... View the full answer