Question: make the table in this format Question2: In a 480 minute shift:- On a machine rated at 100 products output per minute Maximum output =
Question2: In a 480 minute shift:- On a machine rated at 100 products output per minute Maximum output = 480 mins x 100 units = 48000 units Shift info Output (Good Production) - 32000 units Speed =98 units per minute Planned downtime = 82 mins Bottleneck loss due to B/down = 30 mins Rejects (in process) = 1255 in 8 hr shift Output (OEE) - 32000/48000 = 66.7% 480mins x 66.67% = 320 mins, therefore Total Loss = 160 mins Six Loss Calculations: Speed loss Max theoretical units possible at actual speed = 98 x 480 = 47040 = (32000/47040) - (32000/48000) = 68.03% - 66.67% = 1.36% 480 x 1.36% = 6.53 mins / 480 -(1.36%) Planned downtime = 82 mins / 480 = (17.08%) Breakdown = 30 mins / 480 = (6.25%) Rejects = 1255 / 98 (actual running speed) = 12.81 mins / 480 =(2.67%) Minor stops = 480-320-6.53-82-30-12.81 = 28.66 mins / 480 = (5.97%) Total loss = 160 mins = (33,33%) OEE Calculations (Time in mins): Production time = 480 Time less availability loss = 368 Time less performance loss = 333 Availability Loss Performance Loss Quality Loss Planned downtime =82 Speed loss 6.53 Rejects on start up =0 Breakdowns =30 Minor stops (
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
