Question$2$:

In a $480$ minute shift :$-$

On a machine rated at $100$ products output per minute

Maximum output $=480$ mins $100$ units $=48000$ units

Shift info: $,$ Output $($Good Production$)=32000$ units

Speed $=98$ units per minute

Planned downtime $,=82$mins

Bottleneck loss due to $\frac{B}{?}$ down $=30$mins

Rejects $($in process$)=1255$ in $8hr$ shift

Output $($OEE$)=\frac{32000}{48000}=66\mathrm{.}7\%$

$480$mins$66\mathrm{.}67\%=320$mins, therefore Total Loss $=160$mins

Six Loss Calculations:

Speed loss

Max theoretical units possible at actual speed $=98480=47040$

$=(\frac{32000}{47040})-(\frac{32000}{48000})=$

$68\mathrm{.}03\%-66\mathrm{.}67\%=1\mathrm{.}36\%$

$4801\mathrm{.}36\%$

$=6\mathrm{.}53$min$\frac{s}{480},=(1\mathrm{.}36\%)$

Planned downtime

$=82$ mins $\frac{?}{480},=(17\mathrm{.}08\%)$

Breakdown

$=30$ mins $\frac{?}{480},=(6\mathrm{.}25\%)$

$)($actual running speed$)$

$=12\mathrm{.}81$min$\frac{s}{480},=(2\mathrm{.}67\%)$

Minor stops $=480-320-6\mathrm{.}53-82-30-{12\mathrm{.}81}_{?}$

$=28\mathrm{.}66$ mins $\frac{?}{480},=(5\mathrm{.}97\%)$

Total loss $=160$mins,$=(33\mathrm{.}33\%)$

OEE Calculations $($Time in mins$)$:

Production time $=480$ Time less availability loss $=368,$ Time less performance loss $=333$

Availability Loss

OEE $=0\mathrm{.}770\mathrm{.}90\mathrm{.}96=66\mathrm{.}7\%{?}_{?}$

Transform these information into our OEE Table and prove the "availability", "efficiency$(?)",$

"performance", "Reliability$-$Throughput Yield", "OEE" measures with open calculation. To

prepare an Excell sheet is NOT done. Show your calculations,....

What are the major differences, between both approaches $($our and the Case above$)?$

Mention at least three of them

As a consultant where would start? Why explain?