Match the value with the correct name it represents. Use the formula:

$18668\mathrm{.}38=$

$200((1+0\mathrm{.}03/12)7121)(0\mathrm{.}03/12)$

$$

$200$a$.$ the payment

$0\mathrm{.}03$b$.$ the future value

$12$c$.$ the number of years of the investment

$7$d$.$ the annual interest rate

$18668\mathrm{.}38$e$.$ the number of compoundings per year