Question: max 2 = 3x1 + 42 + 5x3. s.t. 21 + 52 + 33 500 1 + 3X2 + 3x3 300 X1, X2, X3 0

max 2 = 3x1 + 42 + 5x3.

s.t.

21 + 52 + 33 500

1 + 3X2 + 3x3 300

X1, X2, X3 0

max 2 = 3x1 + 42 + 5x3. s.t. 21 + 52 + 33 500 1 +

maxz=s.t.3x1+4x2+5x32x1+5x2+3x3500x1+3x2+3x3300x1,x2,x30 For the starting basic feasible solution x1=0,x2=0,x3=0,s1=500 and s2 =300, the corresponding simplex tableau is

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