Question: Maximum Deflection under a Single Wheel in Terms of x 1 w 0 = Y 0 = P ( 6 4 E I k 3

Maximum Deflection
under a Single Wheel in Terms of x1
w0=Y0=P(64EIk3)14,[Eq.3]
x1=4(4EIk)14,[Eq.2]
Rearrange Eq.2 with x1 as the main variable,
substitute in Eq.3, and simplify, to get:
w0=Y0=0.391Pkx1
Maximum Deflection under a Single Wheel in Terms

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