Members AB has rectangular cross$-$section with $32$ mm width and $7$ mm thickness, and the diameter of the pins is $16$ mm $.$

If the maximum allowable average normal stress and average shear stress in member AB are $110$ MPa and $44$ MPa $,$ respectively, then The maximum allowable value of force $\backslash ($ P $\backslash )($in kN $)$ is

One possible correct answer is: $19\mathrm{.}712$

The corresponding average bearing stress, at maximum value of $\backslash ($ P $\backslash ),$ between pin at A and member AB $($in MPa$)$ is

One possible correct answer is: $176$

The corresponding maximum average shear stress, at maximum value of $\backslash ($ P $\backslash ),$ on pin at A $($in MPa$)$ is

One possible correct answer is: $98\mathrm{.}039444944608$