MIPS has memory alignment restriction. If we'd store a 32-bit integer ( locations and the current memory status as follows (shaded ones indicating memory occupied) how many different ways/locations you could store that integer. Note: the memory is byte addressed. 3. i.e. 4 bytes) in memory Mem addr Mem content 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010 1011 1100 1101 1110