Question: Molecular Formula: C 3 H 6 O 2 Mass SpectrumData: UV-VIS Data: Molecular Ion (M + ) 74 m/z No significant UV absorption > 220

Absorbance / % 0 50- 100- 4000 180 (3H) 160 3000 -M

Molecular Formula: C3H6O2

Mass SpectrumData: UV-VIS Data:

Molecular Ion (M+) 74m/z No significant UV absorption > 220 nm.

Fragment 43 m/z (base peak)

Answer the following questions.

11. What is the degree of unsaturation for this compound?

a. 0

b. 1

c. 2

d. 3

12. The peak at 1746 cm-1 on the IR spectrumtells us the compound contains a(n)

a. hydroxyl group

b. primary amine

c. carbonyl group

d. aromatic ring

13. The sharp intense peak at 1246 cm-1 is usuallyindicative of _____________ stretch.

a. carbon-carbon single bond

b. carbon-nitrogen single bond

c. carbon-hydrogen single bond

d. carbon-oxygen single bond

14. Based on the information from the IR spectrum, themajor functional group in this compound is a(n) _____________.

a. alcohol

b. carboxylic acid

c. ester

d. aldehyde

15. Based on the 1H NMR how many sets ofnon-equivalent protons are in this molecule?

a. 1

b. 2

c. 3

d. 4

16. The most deshielded peak in the 13C NMR ischaracteristic of the ______________ group.

a. vinyl carbon

b. sp-hybridized carbon atoms

c. carbonyl carbon atom

d. aromatic carbon atoms

17. The base peak at m/z 43 in the mass spectrum is dueto the loss of ___________ group.

a. OCH3

b. C=O group

c. CH3 group

d. O=CCH3

18. The peak at 3.4 ppm in the 1H NMR is moredownfield than the peak at 2.0 ppm because it is attached to_______________.

a. another carbon atom

b. an oxygen atom

c. more hydrogen atoms

d. more carbon atoms

19. The molecular ion peak at m/z 74 tells us the______________ of the compound.

a. molecular formula

b. melting point

c. molecular weight

d. empirical formula

20. The name and structure of the compound that best fitsthis data is

Absorbance / % 0 50- 100- 4000 180 (3H) 160 3000 -M 140 2500 120 2000 nam Warenumbers/cm 100 PPM 1500 (3H) 2 PPM 18 1000 T 500

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